FEBRUARY 2016 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 CALENDARS Practice Questions Set 3

Question 1: Today it is Monday, after 61 days it will be? (a) Saturday Thursday (b) Tuesday (c) Wednesday (d) Solution 1. Observation: Odd days are No. of days beyond the weekly cycle Monday the counting starts, count No. of Odd days RI61/7] > 5 Odd days Add 5 to Monday, the day that's landed is the answer > Saturday Answer

Question 2: How many days are there in x weeks & x days? (b) 14x (c) 8 (d) 7x2 (a) 8x Solution 2. A week has 7 days > Thus x weeks have 7x days There are x days more to be added -> x more days Total No. of days (7x+ x) 8X days Answer

Question 3: Which of the following is NOT a Leap year (a) 2018 AD 300 AD (b) 2000 AD (c) 400 AD (d) Solution 3. Key point: For a Century to be a Leap year, it is divisible by 400 For any other year to be a Leap year, it is divisible by 4 From options, 300 AD is NOT a Leap year Answer

Question 4: Which of the following years has 2 Odd days? (a) 100 AD(b) 200 AD (c) 300 AD(d) 400 AD Solution 4. Key point: For a Century to be a Leap year, it is divisible by 400 A Leap year has 366 days 2 Odd days & - A ordinary year has 365 days 1 Odd day From options, 400 AD is a Leap year & 100 AD, 200 AD, 300 AD are Ordinary years Year 400 AD has 2 Odd days Answer

Question 5: January 1, 2008 is a Tuesday. On what dates do Thursdays fall in the month of January, 2009? (a) 1st, 8th, 15th, 22nd,30th (b)1st, 8th, 15th, 22nd, 29th (c) 2nd, 9th, 16th, 23rd, 30th (d) 3rd, 10th, 17th, 24th, 31st Solution 3. Observation: Reference date given Simply calculate No. of odd days & add to Tuesday Year 2008 is a Leap year with 366 days > Leap year has 2 Odd days

2 Odd days added to Tuesday Tuesday +2 Thursday Thus, Jan 1st 2009 was a Thursday Jan 8th 2009 was a Thursday Jan 15th 2009 was a Thursday Jan 22nd 2009 was a Thursday Jan 29th 2009 was a Thursday

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Bhavuk Pujara

MDI Gurgaon ‘18 Rank 3rd | CAT 98.3 | NMAT 98.8

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Faisal erayassan

2 years ago

mam pls send telegram channel link

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