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CAT Sample Questions (in Hindi)
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Here we discuss some CAT level Calendars Question, Examples to Find Day of the week

Bhavuk Pujara
MDI Gurgaon ‘18 Rank 3rd | CAT 98.3 | NMAT 98.8

U
Unacademy user
capital Tehran currency rial
  1. FEBRUARY 2016 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 CALENDARS Practice Questions


  2. Day of the week on 2nd March 1912 Question 1: Find Day of the week on 2nd March 1912 Step 1: Simplify the calculation, break the years in Odd days of: [400x + no. of Centuries +(Years in tens 1) (Months - 1)-+ Days] Here, 1600300 11(Jan thru. Feb) + 2 days Step 2: Calculate Odd days of each component 1600 years 400 (4) 400 years has 0 Odd days 1600 vears has 0 Odd days


  3. Day of the week on 2nd March 1912 Step 3: 300 years 300 years has 1 Odd day Step 4. 11 years 11 years has 2 Leap years9 Ordinary years A Leap year has 2 Odd days & An Ordinary year has 1 Odd day 2 x 2 4 Odd days & 9 x 1 9 Odd days R[(4 9)/7] - 6 Odd days


  4. Day of the week on 2nd March 1912 Step 5: Jan thru. Feb Jan. has R[31/7] 3 Odd days Feb. has 1 Odd day (Because 1912 is a Leap year) 4 Odd days Step 6: Thru. 2nd March >2 Odd days


  5. Day of the week on 2nd March 1912 Total Odd days- 0+ 1+6+4 2 - R[13/7] 6 Odd days Answer


  6. Day of the week on 2nd March 1912 Step 7. From Reference table below, 6 Odd days Saturday Reference Chart Number of Odd days Day of the week Sunday Monday Tuesday Wednesday Thursday Friday Saturday 0 2 4 Therefore, It was a Saturday on 2nd Mar 1912


  7. Day of the week on 3rd December 2012 Question 1: Find Day of the week on 3rd December 2012 Step 1: Simplify the calculation, break the years in Odd days of: [400x + no. of Centuries +(Years in tens 1) (Months - 1)-+ Days] Here, 20000 11+(January thru. November) 3 days Step 2: Calculate Odd days of each component 2000 years 400 (4) 400 years has 0 Odd days 2000 vears have 0 Odd days


  8. Day of the week on 3rd December 2012 Step 3: 0 years as remaining centuries 0 Odd days Step 4.11 years 11 years have 2 Leap years +9 Ordinary years A Leap year has 2 Odd days & An Ordinary year has 1 Odd day > 2 x 2 4 Odd days & 9 Odd days 9)/7] 6 Odd days 9 x 1 > RI(4


  9. Day of the week on 3rd December 2012 Step 5: January thru. November Jan. has R[31/71 3 Odd days Feb. has R[29/7] 1 Odd day (Because 2012 is a Leap year, Feb has 29 days) Mar. has R[31/7] 3 Odd days Apr. has R[30/7] 2 Odd days May has R[31/7] 3 Odd days June has R[30/7] 2 Odd days July has R[31/7] 3 Odd days Aug. has R[31/7] 3 Odd days Sep. has R[30/7]-2 Odd days Oct. has R[31/7] 3 Odd days Nov. has RI30/71 2 Odd days


  10. Day of the week on 3rd December 2012 3+1+3+ 2+3 +23+3+2+3+2 Odd day:s R[2717] 6 Odd days Step 6: Thru. 3rd December 3 days 3 Odd days Total Odd days 0 06+ 6+3-1 Odd day Answer