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9 lessons,
47m 23s
Clock Problems - Type I - Example II
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Riya Agarwal is teaching live on Unacademy Plus

Riya Agarwal
The LRDI expert! 4+ years teaching experience. Your personal guide, use code "iriyaagarwal" for discount on plus subscription.

Unacademy user
thanks Ravin sir for your kind information it is very useful for HSSC exams
for example 2: the minute hand has to cover 120° more to form a right angle coz it has already covered 30° to form the first right angle. so it should be (6*30°)=120° isn't it? plz help ma'am I got confused
In part 5, how the minute hand will cover only 210°, in the movement of minute hand the hour hand will also move some distance, so for the formation of right angle the minute hand should be somewhat in between 7 and 8, so the distance covered by the minute hand must be in between 210° and 240°. So why you took 210° to solve the problem .
3 months ago
yes i also have same doubt
Shivam Goswami
3 months ago
exactly how come the hour hand is considered stationary while minute hand is making angles with it...both will be moving hence the question becomes complex but she has simply considered the hour hand to be stationary
why the relative distance is not taken by subtracting it with the hr hand rather the distance covered by the minute hand is only taken as the relative distance. why? please answer mam.