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Number System (Divisibility practice problem - 2) (in Hindi)
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Number System (Divisibility practice problem - 2) (in Hindi)

Bharat Gupta is teaching live on Unacademy Plus

Bharat Gupta
Engineer by degree Mathematician by Heart. Having 22 years of teaching experience. More than 20000 students selected.

Comments
(7)
U
Unacademy user
Mm
sir, I didn't understand how u multiply 3*1+3*9 how it came totally out of mind
Mc
Manisha choudhary
4 months ago
3*1+3*9=30 in this the end unit is 0 thats y the ans is (c)0. 3*1+3*9 where is 1 is end digit when power of 9 is even , & when power of 9 is odd the end digit should be 9
In the last question why we find only 3 digit nos. as it states about natural nos.? In the ap why we take n=100 not any single digit nos?
NJ
sir the no is √288k * x so how can we factorise 288 alone when the no is 288k?
√(288k*x) option B can't be right as if x=12 then also it is divisble by 6 giving the value 2 which will produce the result 24√k.. please check ?
NJ
NAYAN JAIN
a year ago
bro if u take x=12(4*3) then it would become 24√3k rather than 2√k because it will give the value 2 but what about 3 so it will become 24√3k.
NJ
NAYAN JAIN
a year ago
bro if u take x=12(4*3) then it would become 24√3k rather than 2√k because it will give the value 2 but what about 3 so it will become 24√3k.
NJ
NAYAN JAIN
a year ago
bro if u take x=12(4*3) then it would become 24√3k rather than 2√k because it will give the value 2 but what about 3 so it will become 24√3k.
NJ
NAYAN JAIN
a year ago
bro if u take x=12(4*3) then it would become 24√3k rather than 2√k because it will give the value 2 but what about 3 so it will become 24√3k.
NJ
NAYAN JAIN
a year ago
I have written 2√k it should be 24√k.
sir in second question value of B can not be 0 bcz if it will be 0 then it the lst 2 digit will become 50 and it will not be divisible by 4 so ans can not be option ( c) Ans will be option (b)
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