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Reduction by LiAlH4, Frankland Reagent
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We learn the reduction of Alkyl Halides to Alkanes by using 'LiAlH4'. Moreover, Frankland Reagent is also discussed along with a few important examples.

Sachin Rana is teaching live on Unacademy Plus

Sachin Rana
IIT Bombay | Taught three under 100 AIR in JEE Advanced | YouTube: Sachin Rana (180k+ subs) | Qualified NSEA | Passionate Teacher.

Comments
(95)
U
Unacademy user
UBI scheme ...by Sikkim + first of type Sir..I think the drawback of this scheme is population growth , Being lazy and men will snatch the part of money from their wives ..so need some ardent actions to inhibit this practice ..my personal thinking only🙏
Thats true!
VP
bro i have a doubt in the 3rd slide in that example what if we have other than methyl, like one methyl group,one ethyl and propyl, with which group the tertiary carbon forms double bond?
Ishmeet singh
3 years ago
Methyl group probably as it will offer much less steric hindrance then rest , as it is necessary to attack the carbon atom which is next to carbon atom attached to halide
VP
Vinay Patel
3 years ago
can you please elaborate it? why does steric hinderance come in deciding which hydrogen to lose?
Rajat verma
3 years ago
since the alkene is formed by the formation of a carbocation ( one that is directly attached to a halogen).. and a carbanion so,on that basis I think that methyl grp becoz it will form 1 degree carbanion as intermediate which will be more stable
Rajat verma
3 years ago
as the order of stability of carbanion is 1>2>3
VP
Vinay Patel
3 years ago
i think propyl is the correct because of hyperconjugation
VP
Vinay Patel
3 years ago
i think propyl is the correct because of hyperconjugation
Rajat verma
3 years ago
hyperconjugation is same in both ethyl n propyl
VP
Vinay Patel
3 years ago
oh ok thanks
I guess H- will attack the ethyl group alpha carbon and double bond will be formed with ethyl as 1)it would give 7 hyperconjugative structures 2) Why not propyl - As propyl would be too bulky for H- to attack. Methyl would give only 4 alpha H and 4 hyp. conj. structures. Pl. correct if wrong.
If we've Alkyl halides attached to all carbons of a benzene ring and then, if we add 1 mole LiAlH4 to it, will all the alkyl halides get reduced? Or only four of them will get reduced because LiAlH4 can give only 4H-?
Sachin Rana
3 years ago
If they're attached to benzene ring, then none of them will get replaced.
Aditya Mallick
3 years ago
Is it because of resonance effect?
No LiAlH4 reduces only aliphatic carbons
Devansh Bansal
2 years ago
but bro The halides will be indirectly attached to benzene ring so they should get reduced?
Devansh Bansal
2 years ago
but bro halide group will be indirectly attached to the benzene ring so it should get reduced??
Devansh Bansal
2 years ago
but bro halide group will be indirectly attached to the benzene ring so it should get reduced??
Devansh Bansal
2 years ago
but bro halide group will be indirectly attached to the benzene ring so it should get reduced??
Devansh Bansal
2 years ago
but bro halide group will be indirectly attached to the benzene ring so it should get reduced??
Devansh Bansal
2 years ago
but bro halide group will be indirectly attached to the benzene ring so it should get reduced??
Devansh Bansal
2 years ago
but bro halide group will be indirectly attached to the benzene ring so it should get reduced??
Devansh Bansal
2 years ago
but bro halide group will be indirectly attached to the benzene ring so it should get reduced??
Devansh Bansal
2 years ago
but bro halide group will be indirectly attached to the benzene ring so it should get reduced??
Devansh Bansal
2 years ago
but bro halide group will be indirectly attached to the benzene ring so it should get reduced??
Devansh Bansal
2 years ago
but bro halide group will be indirectly attached to the benzene ring so it should get reduced??
Devansh Bansal
2 years ago
but bro halide group will be indirectly attached to the benzene ring so it should get reduced??
Devansh Bansal
2 years ago
but bro halide group will be indirectly attached to the benzene ring so it should get reduced??
Devansh Bansal
2 years ago
but bro halide group will be indirectly attached to the benzene ring so it should get reduced??
Milind Jha
a year ago
if alkyl halides are attached to the benzene ring...then they must get reduced...though only 4 of them...but if halides are attached then none of the carbons shall get reduced
Milind Jha
a year ago
am i right sir??
when LiAlH4 reacts with tertiary carbon, the Hydronium ion will not attack the tertiary carbon... is this because of its bulkyness?? or any other reasons?
Sachin Rana
3 years ago
Due to stearic hinderence or bulkiness.
Utkarsh Puri
3 years ago
and what in case of secondary carbon??
Utkarsh Puri
3 years ago
its major product is an alkene or alkane?
Utkarsh Puri
3 years ago
?????
Sachin Rana
3 years ago
Alkane
Utkarsh Puri
3 years ago
thanks sir
Utkarsh Puri
3 years ago
sir you are doing suchh a good job......keep it up
Utkarsh Puri
3 years ago
and please, if possible provide us witb 5-6 lectures on conversions also.....advanced level ....that will be so nice of you☺☺☺
does the tertiary alkyl halide give alkene as major product on reduction with LiAlH4 due to steric reasons
Sachin Rana
3 years ago
Yes.
Madhusmita Sethi
3 years ago
My doubt is cleared
great deal of work brother. keep it up. is these videos covering all jee advanced topics and realated questions
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